A boy throws balls into air at regular interval of 2 second. The next ball is thrown when the velocity of first ball is zero. How high do the ball rise above his hand? [Take `g=9.8m//s^(2)`]

A person throws balls into the air one after the other at an interval ofone second. The next ball is thrown when the velocityof the ball thrown earlier is zero. To what height the ball rise:

A person throws balls into the air one after the other at an interval ofone second. The next ball is thrown when the velocityof the ball thrown earlier is zero. To what height the ball rise:

A person throws balls into air vertically upward in regular intervals of time of one second . The next ball is thrown when the velocity of the ball thrown earlier becomes zero . The height to which the balls rise is … (Assume , g = 10 ms^(-2) )

A boy throws balls into air.He throws one, whenver the previous one is at its highest point. How high do the balls rise if he throws one ball each sec ?

A man throws balls into air one after another throwing one the other is at the highest point. How high the balls rise , if he throws twice a second ?

A ball is thrown up with a speed of 15 m//s . how high will it go before it begins to fall ? Take g=9.8 m//s^(2) .

A man is standing on top of a building 100 m high. He throws two ball vertically, one at t=0 and after a time interval (less than 2 seconds). The later ball is thrown at a velocity of half the first. At t=2 , both the balls reach to their and second ball is +15m . Q. The time interval between the throw of ball is

A person throws balls upward in regular intervals of time of 2 s. What should be the speed of throwing of balls such that both balls remain in air ?

A person throws balls upward in regular intervals of time of 2 s. What should be the speed of throwing of balls such that both balls remain in air ?