If I is the incentre of a `!ABC` , then `IA:IB:IC` is equal to

If I is the incenter of DeltaABC, then the ratio IA:IB:IC is equal to

If I is the incenter of a triangle ABC, then the ratio IA:IB:IC is equal to cosec (A)/(2):csc(B)/(2):csc(C)/(2)sin(A)/(2):sin(B)/(2):sin(C)/(2)sec(A)/(2):sec(B)/(2):sec(C)/(2) none of these

If I is the incenter of a triangle ABC,then the ratio IA IB IC is equal to

In Delta ABC if I is the incentre then the ratio IA : IB : IC is

If I is the incentre of a !ABC such that angleA=60^(@) , then AI =

If I is the incentre of triangle ABC and angle A = 60^@ , then the value of angle BIC is

I is the incentre of Delta ABC , Produced AI bisects BC at D. Prove that Delta ABC is isosceles.

Assertion: If I is the incentre of /_\ABC, then |vec(BC)| vec(IA) +|vec(CA)| vec(IB) +|vec(AB)| vec(IC) =0 Reason: If O is the origin, then the position vector of centroid of /_\ABC is (vec(OA)+vec(OB)+vec(OC))/3