Bond energies of `H-H and Cl-Cl` are `"430 kJ mol"^(-1)` and `"242 kJ mol"^(-1)` respectively. `DeltaH_(f)` for HCl is `"91 kJ mol"^(-1)`.
What will be the bond energy of `H-Cl`?

Given the bond energies of H - H and Cl - Cl are 430 kJ mol^(-1) and 240 kJ mol^(-1) , respectively, and Delta_(f) H^(@) for HCl is - 90 kJ mol^(-1) . Bond enthalpy of HCl is

Given the bond energies of H - H and Cl - Cl are 430 kJ mol^(-1) and 240 kJ mol^(-1) , respectively, and Delta_(f) H^(@) for HCl is - 90 kJ mol^(-1) . Bond enthalpy of HCl is

Given that bond energies H-H and Cl-Cl are 430 kJ mol^(-1) and 240 kJ mol^(-1) respecively and Delta_(f) H for HCl is - 90 kJ mol^(-1) . Bond enthalpy of HCl is :

The bond enthalpies of H-H and Cl-Cl are 430 and 242 kJ mol^(-1) , respectively. If DeltaH_(f) (HCl) is -91 kJmol^(-1) the bond enthalpy of HCl would be

Calculate the bond energy of H-Cl bond, given that the bond energies of H–H, CI—Cl bonds are 433 kJ mol^(-1) and 242 kJ mol^(-1) respectivly. The DeltaH_f for HCl is -91 kJ" " mol^(-1) .

The bond enthalpies of H-H and CI-CI are 430 and 242 kJ mol^(-1) , respectively. If DeltaH_(f) (HCI) is -91 kJmol^(-1) the bond enthalpy of HCI would be

The bond energies of H-H and l - I bonds are 435 kJ mol^-1 and 150 kJ mol^-1 respectively. If deltaH_t^O for Hl is 26.5 kJ mol^(-1) then bond enthalpy of H-l bond is