In the given diagram, PQ and RS are common tangents to the two circles with centres C and D. Find the length of PQ and hence area of trapexium RSDC.

In the figure, PQ and RS are the common tangents to two circles intersecting at O. Prove that PQ=RS

In the figure, PQ is a tangent of length 6 cm to the circle with centre O and |__OQP=60^(@) . Find OQ.

In the given figure,PQ is tangent at a point R of the circle with centre O.If,find m/_PRS .

In fig. PQ is a tangent to length 6cm to the circle with centre O and angle OQP=60^@ . Find OQ

In the give figure ,PQ and PR are tangents to the given circle such that PQ =5 cm and angleQPR=60^(@) . The length of chord QR is

Two circles of radii 8 cm and 2 cm respectively touch each other externally at the point A. PQ is the direct common tangent of these two circles of centres O_(1) and O_(2) respectively. The length of PQ is equal to :

In the figure, PQ is tangent to a circle with centre O. OQ=12, PQ=6. Find the area of the shaded portion