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[" In the figure the sides "AB" and "AC" of a triangle "ABC" are produced to point "],[" Eand "D" respectively.If bisectors "BO" and "CO" of "/_CBE" and "/_BCD" respectively "],[" meet at point ' "O" ' then prove that "/_BOC=90-1/2/_BAC" ."]

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In Fig. 6.38, the sides AB and AC of ABC are produced to points E and D respectively. If bisectors BO and CO of CBE and BCD respectively meet at point O, then prove that /_B O C=90o-1/2/_B A C .

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