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Find the values of the letters and give reasons for the steps involved. `AB xx 3 =CAB`

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Given that AB×3=CAB
For B×3 to end with B it has to be either 0 or 5, as this are the only numbers which when multiplied will give the same number.
so taking B=5, we get carry-over, which will not give the next product as C A.
Thus, B=0.
Also, `A×3` ends with A, so `A=5.`
And `3×5=15` ∴ `C=1`
Hence, A=5,B=0 and C=1.
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