" If "H" is the orthocentre of "/_ABC" and if "AH=x,BH=y,CH=z" ,then "(a)/(x)+(b)/(y)+(c)/(z)=

If H is the orthocenter of Delta ABC and if AH=x,BH=y,CH=z, then (a)/(x)+(b)/(y)+(c)/(z)=

If H is the orthocentre of DeltaABC and AH=x, BH=y, CH=z then (abc)/(xyz)=

IF H is the orthocentre of Delta ABC and if AH=x, BH=y, CH=z, then a/x+b/y+c/z=

If H is the orthocenter of DeltaABC and if AH = x, BH = y, CH = z , then a/x+b/y+c/z=

In Delta ABC is H is the orthocentre of Delta ABC and x= AH, y=BH, z=CH, then x+y+z=

If in Delta ABC , the distance of the vertices from the orthocenter are x,y, and z then prove that (a)/(x) + (b)/(y) + (c)/(z) = (abc)/(xyz)

If in Delta ABC , the distance of the vertices from the orthocenter are x,y, and z then prove that (a)/(x) + (b)/(y) + (c)/(z) = (abc)/(xyz)

If in Delta ABC , the distance of the vertices from the orthocenter are x,y, and z then prove that (a)/(x) + (b)/(y) + (c)/(z) = (abc)/(xyz)

If H is the orthocentre of triangle ABC, R = circumradius and P=AH+BH+CH, then