The ratio of the distance through which a body falls in 4th, 5th and 6th second is starting from rest

The ratio of the distance through which a ball falls in the 2^(nd), 3^(rd) and 4^(th) second is (the initial velocity of the ball is zero)

A body starts from rest, if the ration of the distance travelled by the body during the 4th and 3rd second is x/5 . Find the valud of x.

For a stone what is the ratio of the distances covered in its 1st,3rd and 5th seconds of its free fall.

For a stone what is the ratio of the distance covered in its 1st, 3rd and 5th seconds of its free fall.

A body starts from rest. What is the retio of the distance traveled by the body during the 4^(th) and 3^(rd) seconds

The distance through which a heavy body falls from rest varies as the square of the time of fall . If the body falls 400 feet in 5 seconds then find the distance through which it will fall in 10 seconds and in the tenth second .

A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the 5th second to that covered in 5 seconds is

Name the elements with which even and odd series of 4th, 5th and 6th periods begin.

A body starts from rest. The ratio of the distances travelled by it during the 4th and 3rd second is