" Fílld "24+10times101quad x^(2)-2sqrt(2)n+1=0" of the sind of "2" is "

x^(2)+2sqrt(3)x-24

x^2+2sqrt(3)x-24

(1) x^(2)-(sqrt(2)+1)x+sqrt(2)=0

x^(2)-10x-24=0

Factorise : x^2+sqrt(2)x-24

In the expression 24 -[2.4 -{0.24 xx 2- (0.024 - x)}] = 22.0589 , the value of x is

If (0,1),(1,1)a n d(1,0) be the middle points of the sides of a triangle, its incentre is (2+sqrt(2),2+sqrt(2) ) (b) [2+sqrt(2),-(2+sqrt(2))] (2-sqrt(2),2-sqrt(2)) (d) [2-sqrt(2),(2+sqrt(2))]

If (0,1),(1,1)a n d(1,0) be the middle points of the sides of a triangle, its incentre is (2+sqrt(2),2+sqrt(2) ) (b) [2+sqrt(2),-(2+sqrt(2))] (2-sqrt(2),2-sqrt(2)) (d) [2-sqrt(2),(2+sqrt(2))]

Let S_n=1+q+q^2 +...+q^n and T_n =1+((q+1)/2)+((q+1)/2)^2+...((q+1)/2)^n If alpha T_100=^101C_1 +^101C_2 x S_1 ...+^101C_101 x S_100, then the value of alpha is equal to (A) 2^99 (B) 2^101 (C) 2^100 (D) -2^100