[" Q3.The speed at the maximum height of a projectile is "(sqrt(3))/(2)" times of its initial speed ta' of "],[" projection.Its range on the horizontal plane: "]

The speed at the maximum height of a projectile is sqrt(3)/(2) times of its initial speed 'u' of projection Its range on the horizontal plane:-

The speed at the maximum height of a projectile is sqrt(3)/(2) times of its initial speed 'u' of projection Its range on the horizontal plane:-

The speed at the maximum height of a projectile is sqrt(3)/(2) times of its initial speed 'u' of projection Its range on the horizontal plane:-

The velocity at the maximum height of a projectile is sqrt(3)/2 times the initial velocity of projection. The angle of projection is

The velocity at the maximum height of a projectile is sqrt(3)/2 times the initial velocity of projection. The angle of projection is

The speed at the maximum height of a projectile is (1)/(3) of its initial speed u. If its range on the horizontal plane is (n sqrt(2)u^(2))/(9g) then value of n is

The speed at the maximum height of a projectile is (1)/(3) of its initial speed u. If its range on the horizontal plane is (n sqrt(2)u^(2))/(9g) then value of n is

The velocity at the maximum height of a projectile is half of its velocity of projection u . Its range on the horizontal plane is

The velocity at the maximum height of a projectile is half of its velocity of projection u . Its range on the horizontal plane is