" For "x>1," show that "2log_(10)x-log_(x)(0.01)>=4

For xgt1 , show that: 2log_10x-log_x 0.01ge4

solve for x:2log_(10)x-log_(x)(0.01)=5

solve for x: 2log_10x-log_x(0.01)=5

Select the correct answer (MCQ) : (iv) The least value of the quantity 2log_(10)(x) - log_(x)(0.01)[x > 1] =

For x>1, the minimum value of 2log_(10)(x)-log_(x)(0.01) is

The least value of the expression 2(log)_(10)x-(log)_(x)(0.01)* for x>1 is (a) 10 (b) 2(c)-0.01(d)4

The least value of the expression 2(log)_(10)x-(log)_(x)(0.01), for x>1, is (1980,2M)(a)10(b)2(c)-0.01(d) None of