log1+log(1)/(2)+log(2)/(3)+log(3)/(4)+...+1....+log_(100)90-log100=

log(1/2)+log (2/3)+log(3/4) +….+ log(99/100) = ______

log_(100)4+2log_(100)27

log2+log(1+(1)/(2))+log(1+(1)/(3))+.........+log(1+(1)/(n-1))=

log4+(1+(1)/(2x))log3=log(3^((1)/(x))+27)

The value of log_(2)*log_(3)dots......log_(100)100^(99)

Given log_2(a) + log_2(2) + log_3(1 + b^2)=2 (a>1. b in R),c=log_10(2^log_2(3)......log_99(100)),d=log_10(2^log_2(3^log_3(4........log_99(100) Then find the value of (a+b+c+d).

log_(2)log_(3)log_(4)(x-1)>0

The number N=2^(log_(2)3log_(3)4*log_(4)5.......log_(99)100) simplifies to

log^(2)(100x)+log^(2)(10x)=14+log((1)/(x))