The radius of the earth is `6.37xx10^(6)m`, its mean density is `5.5xx10^(3)Kg m^(-3)` and G=`6.66xx10^(-11)Nm^(2)Kg^(-2)` . Determine the gravitational potential on the surface of the earth.

The radius of the earth is 6.37 xx 10^(6) m and its mean density is 5.5 xx 10^(3) "kg m"^(-3) and G = 6.67 xx 10^(-11) "N-m"^(2) kg^(-2) Find the gravitational potential on the surface of the earth.

The radius of the earth is 6.37 xx 10^(6) m and its mean density is 5.5 xx 10^(3) "kg m"^(-3) and G = 6.67 xx 10^(-11) "N-m"^(2) kg^(-2) Find the gravitational potential on the surface of the earth.

Determine the gravitational potential on the surface of earth, given that radius of the earth is 6.4 xx 10^(6) m : its mean density is 5.5 xx 10^(3)kg m^(-3) , G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

A satellite revolves around the earth at a height of 1000 km. The radius of the earth is 6.38 xx 10^(3) km. Mass of the earth is 6xx10^(24)kg and G=6.67xx10^(-14)"N-m"^(2)kg^(-2) . Determine its orbital velocity and period of revolution.

The radius of the earth is 6.38 xx10^8 cm. its mean density is 5.5 g*cm ^(-3) and the universal gravitational constant is 6.67xx10^(-8) CGS unit. What is the gravitational potential at any point on the earth's surface ?

The radius of the earth is 6.37xx10^(6) m its mass 5.98xx10^(24) kg determine the gravitational potential on the surface of the earth Given G=6.67 xx10^(-11) N-m^(2)//khg^(2)

An artificial satellite revolves round the earth at a height of 1000 km . The radius of the earth is 6.38xx10^(3)km . Mass of the earth 6xx10^(24)kg,G=6.67xx10^(-11)Nm^(2)kg^(-2) . Find the orbital speed and period of revolution of the satellite.

The radius of earth is 6.37xx10^6 m , its mean density is 5.5 g*cm^(-3) . Calculate the earth's surface potential.