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[" 48] The pH of "10^(-3)MNH(4)OH(K(b)=1...

[" 48] The pH of "10^(-3)MNH_(4)OH(K_(b)=10^(-5))" is "],[[" 1) "3," 2) "11],[" ."3" ) "10," 4) "4]]

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The pH of the 10^(-3)M NH_(4)OH(Kb = 10^(-5)) is

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Calculate the pH of 0.1 M NH_4 OH if K_b =1.75 xx10^(-5) .

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The pH of 0.02MNH_(4)Cl solution will be : [Given K_(b) (NH_(4)OH) = 10^(-5) and log 2 = 0.301 ]

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