If young's modulus of steel is `2xx10^(11)N//m^(2)`, then the force required to increase the length of a wire of cross section `1 cm^(2)` by `1%` will be

For steel Y=2xx10^(11) Nm^(-2) . The force required to double the length of a steel wire of area 1 cm^(2) is

Force required to increase the length of wire of area of cross section .A. by one percent, if .Y. is young.s modulus, is

The area of a cross section of steel wire is 0.1cm^2 and Young's modulus of steel is 2xx10^(11)Nm^-2 . The force required to strech by 0.1% of its length is

If Y is the Young's modulus of a wire of cross sectional area A, then the force required to increase its length by 0.1% will be

A steel wire 4.0m in length is stretched through 2.0mm .The cross -sectional area of the wire is 2.0 mm^(2) .If young's modulus of steel is 2.0xx10^(11) N//m^(2) (a) the enrgy density of wire, (b) the elastic potential energy stored in the wire.

A 20 N stone is suspended from a wire and its length changes by 1% . If the Young's modulus of the material of wire is 2xx10^(11)N//m^(2) , then the area of cross-section of the wire is 2xx10^(11)N//m^(2) , then the area of cross-section of the wire will be

A steel wire 4.0m in length is stretched through 2.0mm .The cross -sectional area of the wire is 2.0 mm^(2) .If young's modulus of steel is 2.0xx10^(11) N//m^(2) (a) the energy density of wire, (b) the elastic potential energy stored in the wire.

A 20 N stone is suspended from a wire and its length changes by 1% . If the Young's modulus of the material of wire is 2xx10^(11)N//m^(2) , then the area of cross-section of the wire will be

Calculate the force required to increase the length of a steel wire of cross- sectional area 10^(-6)m^(2) by 0.5% given: Y_(("for steel"))=2xx10^(11)N-m^(2)

Calculate the force required to incrase the length of wire of cross-sectional area 10^(-6) m^(2) by 50% if the Young's modulus of the material of the wire is 90 xx 10^(9) Pa .