Home
Class 12
CHEMISTRY
[" 3] A quantity of "0.3" gm of Cu was d...

[" 3] A quantity of "0.3" gm of Cu was deposited from CuSO "_(4)" solution by passing "4" A through the solution for "],[3.8" min.Calculate the value of Faraday constant.(Atomic mass of "Cu=63.5gmmol^(-1)" ) "]

Promotional Banner

Similar Questions

Explore conceptually related problems

0.369 gm of copper was deposited an passing 0.750 A of current through a CuSO_4 solution for 25 minutes . Calculate the atomic mass of copper.

2.5 amperes of current is passed through copper sulphate solution for 30 minutes. Calculate the number of copper atoms deposited at the cathode (Cu = 63.54).

20 ampere current is flowing through CuSO_4 solution for 60 minutes. Find the amonut of cupper deposited. (At .wt. of Cu = 63.5)

A current of 0.25 amp is passed through CuSO_(4) solution for 45 minutes. Calculate the mass of copper deposited on the cathode (At.wt of Cu = 63 .)