A relation `R,NrarrN` defined by `R={(x,y)//y=x^(2)+1)` is

A relation R: ZrarrZ defined by R={(x,y)//y=x^(2)-1} is

Let R be a relation on N defined by R={(x,y):x+2y=8). Then domain of R is

Determine the domain and range of the relation R defined by R={(x,y):y=x+1} , x in {0,1,2,3,4,5,6}

If A = {2,3,4,5,6) and R is a relation on set A defined by R= {(x, y): y=x+2, X, y in A} then

Let R be a relation defined as R={(x,y):y=sqrt((x-1)^(2)),x varepsilon Z and -3<=x<=3} Relation R is equals to :

a={1,2,3,4,5} , Relation R on A is defined by R={(x,y)//x lt y" and "|x^(2)-y^(2)|lt 9} then R =

Let R be a relation defined as R={(x,y) : y=sqrt((x-1)^2) , xepsilon Z and -3<=x<=3} Relation R is equals to :

Let R be a relation on N defined by R={(x,y):2x+y=10}, then domain of R is

Let A={1,2,3,……,13,14} ,R is the relation on A defined by R={(x,y):3x-y=0 , x,y in A} Write R in a tabular form.

Let A={1,2,3,……,13,14} ,R is the relation on A defined by R={(x,y):3x-y=0 , x,y in A} Find the domain and range of R.