" If "n" is the number of fissions per second and "E" is the energy released per fission then power of nuclear reactor is "

The enegry released per fission of .^(235)u is nearly

In a nuclear reactor, the number of U^(235) nuclei undergoing fissions per second is 4xx10^(20). If the energy releases per fission is 250 MeV, then the total energy released in 10 h is (1 eV= 1.6xx10^(-19)J)

(a) Calculate the energy released by the fission of 2g of ._(92)U^(235) in kWh . Given that the energy released per fission is 200MeV . (b) Assuming that 200MeV of enrgy is released per fission of uranium atom, find the number of fissions per second required to released 1 kilowatt power. (c) Find the amount of energy produced in joules due to fission of 1g of ._(92)U^(235) assuming that 0.1% of mass is transformed into enrgy. ._(92)U^(235) = 235 amu , Avogadro number = 6.023 xx 10^(23)

Most of energy released in the fission is carried by

10^14 fissions per second are taking place in a nuclear reactor having efficiency 40% . The energy released per fission is 250MeV. The power output of the reactor is

10^(14) Fission per second are taking place in a nuclear reactor having efficiency 25 %. The energy released per fission in 200 MeV. The power output of the nuclear reactor

In the nuclear fission of ""_(92)U^(235) , 200 MeV of energy is released per fission. Calculate the output power of the reactor if 3 kg of fuel is used in 40 days.

Nuclear Fission||Nuclear Fusion||Nuclear Reactor

During the fission process of Uranium, the amount of energy liberated per fission is nearly