When `0.2M` solution of acetic acid is neutralised with `0.2M NaOH` in `500 mL` of water, the `pH` of the resulting solution will be: `[pK_(a)` of acetic acid `= 4.74]`

A 100 mL 0.1(M) solution of ammonium acetage is diluted by adding 100 mL of water. The pH of the resulting solution will be ( pK_(a) of acetic acid is nearly equal to pK_(b) of NH_(4)OH )-

20 mL 0.1 (N) acetic acid is mixed with 10 mL 0.1 (N) solution of NaOH. The pH of the resulting solution is (pK_a of acetic acid is 4.74)

A 100 ml 0.1 (M) solution of ammonium acetate is diluted by adding 100 ml of water. The pH of the resulting solution will be ( pK_(a) of acetic acid is nearly equal to pk_(b) of NH_(4)OH

Calculate the pH of 0.05M sodium acetate solution, if the pK_(a) of acetic acid is 4.74 .

Calculate the pH of 0.05M sodium acetate solution, if the pK_(a) of acetic acid is 4.74 .

A 100 mL,0.1 (M), solution of ammonium acetate is diluted by adding 100 mL of water. The pH of the resulting solution will be (pk_a of acetic acid is nearly equal to pK_b of NH_4OH )