`"sin"(5pi)/(12)*"cos"(pi)/(12)` का मान . . . . . . . है ।

2sin((5 pi)/(12))(sin((pi)/(12)))=

"sin" pi/12 "sin" (5pi)/12=

2sin((5pi)/12) sin(pi/12)=.........

Prove that (i) "sin " (7pi)/(12) " cos " (pi)/(2) - "cos " *(7pi)/(12) " sin " (pi)/(4) = (sqrt(3))/(2) (ii) " sin " (pi)/(4) " cos " (pi)/(2) + "cos"(pi)/(4) " sin " (pi)/(12) = (sqrt(3))/(2) (iii) " cos " (2pi)/(3) " cos " (pi)/(4) - " sin " (2pi)/(3) " sin " (pi)/(4) =(-(sqrt(3) +1))/(2sqrt(2))

Prove that 2"sin"(5pi)/(12)"cos"(pi)/(12)=(sqrt3+2)/2

Prove that (i) " 2sin " (5pi)/(12) " sin " (pi)/(12)=(1)/(2) (ii) " 2 cos " (5pi)/(12) " cos " .(pi)/(12)=(1)/(2) (iii) " 2 sin ".(5pi)/(12) " cos " (pi)/(2) = ((2+sqrt(3))/(2))

Prove that (i) " 2sin " (5pi)/(12) " sin " (pi)/(12)=(1)/(2) (ii) " 2 cos " (5pi)/(12) " cos " .(pi)/(12)=(1)/(2) (iii) " 2 sin ".(5pi)/(12) " cos " (pi)/(2) = ((2+sqrt(3))/(2))

sin((7pi)/(12))cos(pi/4)-cos((7pi)/(12))sin(pi/4)=...........

16 * cos ""(pi)/(12) * cos"" (4pi)/(12) * cos"" (5pi)/(12)= A) sqrt1 B) sqrt2 C) sqrt3 D) sqrt4