The voltmeter shown in figure reads 18V across the `50(Omega)`resistor. Find the resistance of the voltmeter.

The voltmeter shown in fig, reads 6V across the 60 Omega resistor. Then the resistance of the voltmeter is-

The voltmeter shown in the figure reads 10V across 40 omega . The resistance of voltmeter is

Two resistors 10Omega and 25Omega are connected in series and the combination is connected across a 25 V source of negligible internal resistance. A voltmeter of resistance 25Omega is connected across the 10Omega resistor. Find the reading in the voltmeter. If another voltmeter of a very large resistance replaces the voltmeter, then find the reading of voltmeter.

The voltmeter reads 40 V across 60 Omega resistance. The resistance of voltmeter is. .

50 Omega and 100 Omega resistors are connected in series. This connection is connected with a battery of 2.4 volts. When a voltmeter of 100 Omega resistance is connected across 100 Omega resistor, then the reading of the voltmeter will be

50 Omega and 100 Omega resistors are connected in series. This connection is connected with a battery of 24 volts. When a voltmeter of 100 Omega resistance is connected across 100 Omega resistor, then the reading of the voltmeter will be

In the circuit shown in figure-3.387, the voltmeter is having a resistance 4000 Omega . Find the percentage error in reading of this voltmeter.

50 Omega and 100 Omega resistors are connected in series. This connection is connected with a battery of 2.4 volts. Whne a voltmeter, then the reading of the voltmeter will be 100 Omega resistor, then eh reading of the voltmeter will be

A voltmeter of resistance 998 Omega is connected across a cell of emf 2 V and internal resistance 2 Omega . Find the p.d. across the voltmeter, that across the terminals of the cell and percentage error in the reading of the voltmeter.