Find the term independent of x in the expansion of `(3/2x^2-1/(3x))^6`.

Explanation

To find the term independent of \( x \) in the expansion of \( \left( \frac{3}{2}x^2 - \frac{1}{3x} \right)^6 \), we will follow these steps:

### Step 1: Write the General Term
The general term \( T_{r+1} \) in the binomial expansion of \( (a + b)^n \) is given by:
\[ T_{r+1} = \binom{n}{r} a^{n-r} b^r \]
In our case, \( a = \frac{3}{2}x^2 \), \( b = -\frac{1}{3x} \), and \( n = 6 \). Therefore, the general term becomes:
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