We have taken a saturated solution of `AgBr`, whose `K_(sp)` is `12xx10^(-14).` If `10^(-7)M` of `AgNO_(3)` are added to `1L` of this solutino, find the conductivity `(` specific conductance `)` of the solution in terms of `10^(-7)S m^(-1)` units.
Given `:`
`lambda^(@)._((Ag^(o+)))=6xx10^(-3)S m^(2) mol^(-1)`
`lambda^(@)._((Br^(c-)))=8xx10^(-3)S m^(2)mol^(-1)`
`lambda^(@)._((NO_(3)^(C-)))=7XX10^(-3)S m^(2) mol^(-1)`

We have taken a saturated solultion of AgBr, K_(SP) is 12 xx 10^(-4) . If 10^(-7) M of AgNO_(3) are added to 1 L of this solution, find conductivity (specific conductance) of this solution in term of 10^(-7) Sm^(-1) units. Given, lambda_((Ag^(+)))^(@) = 6 xx 10^(-3) Sm^(2) mol^(-1) , lambda_((Br^(-)))^(@) = 8 xx 10^(-3) Sm^(2) mol^(-1) , lambda_((NO_(3)^(-)))^@ = 7 xx 10^(-3) Sm^(2) mol^(-1) . Neglect the contribution of solvent.

We have taken a saturated solultion of AgBr, K_(SP) is 12 xx 10^(-4) . If 10^(-7) M of AgNO_(3) are added to 1 L of this solution, find conductivity (specific conductance) of this solution in term of 10^(-7) Sm^(-1) units. Given, lambda_((Ag^(+)))^(@) = 6 xx 10^(-3) Sm^(2) mol^(-1) , lambda_((Br^(-)))^(@) = 8 xx 10^(-3) Sm^(2) mol^(-1) , lambda_((NO_(3)^(-)))^@ = 8 xx 10^(-3) Sm^(2) mol^(-1) . Neglect the contribution of solvent.

We have taken a saturated solution of AgBr,K_(sp) of AgBr is 12xx10^(-14) . If 10^(-7) "mole" of AgNO_(3) are added to 1 litre of this solution then the conductivity of this solution in terms of 10^(-7) Sm^(-1) units will be: [Given: lambda_((Ag^(+)))^(@)=4xx10^(-3)Sm^(2)"mol"^(-1),lambda_((Br^(-)))^(@)=6xx10^(-3) S m^(2) "mol"^(-1),lambda_((NO_(3)^(-)))^(@)=5xx10^(-3)Sm^(2) "mol"^(-1) ]

We have taken a saturated solution of AgBr.K_(sp) of AgBr is 12xx10^(-14) . If 10^(-7) mole of AgNO_(3) are added to 1 mitre of this solutio then the conductivity of this solution in terms of 10^(-7)Sm^(-1) units will be [given lamda((Ag^(+)))^(@)=4xx10^(-3)Sm^(2)mol^(-1)lamda_((Br^(-)))^(@)=6xx10^(-3)Sm^(2)mol^(-1). lamda_((NO_(3)^(-)))^(@)=5xx10^(-3)Smmol^(-1)) (A). 39 (B). 55 (C). 15 (D). 41

We have taken a saturated solution of AgBr.K_(sp) of AgBr is 12xx10^(-14) . If 10^(-7) mole of AgNO_(3) are added to 1 mitre of this solutio then the conductivity of this solution in terms of 10^(-7)Sm^(-1) units will be [given lamda((Ag^(+)))^(@)=4xx10^(-3)Sm^(2)mol^(-1)lamda_((Br^(-)))^(@)=6xx10^(-3)Sm^(2)mol^(-1). lamda_((NO_(3)^(-)))^(@)=5xx10^(-3)Smmol^(-1)) (A). 39 (B). 55 (C). 15 (D). 41

We have taken a saturated solution of AgBr, whose K_(sp) is 12xx10^(-14 . If 10^(-7)M" of "AgNO_(3) are added to 1 L of this solution, find the conductivity of the solution in terms of 10^(-7)"S.m"^(-1) units. Given that lambda^(@) values of the Ag^(+), Br^(-) and NO_(3)^(-) ions are 6xx10^(-3), 8xx10^(-3) and 7xx10^(-3)"S.m"^(2)."mol"^(-1) respectively.