In Fig. 3, ABC is a right triangle, right angled at C and D is the mid-point of BC. Prove that `AB^2 = 4AD^2 - 3AC^2`.

∆ABC is a right angled at B and D is mid-point of BC. Prove that AC^2 = 4AD^2 - 3AB^2 .

ABC is a right triangle , right angled at A and D is the mid point of AB . Prove that BC^(2) =CD^2 +3BD^(2) .

In triangle ABC , angle C = angle 90 , D is the mid point of BC, Prove that AB^2 = 4AD^2 -3AC^2 .

In triangle ABC , angle C = angle 90 D is the mid point of BC, prove that AB^2 = 4AD^2-3AC^2 .

In a right ABC right-angled at C, if D is the mid-point of BC, prove that BC^(2)=4(AD^(2)-AC^(2))

ABC is a right triangle right angled at C and AC = sqrt3BC . Prove that angleABC= 60^(@) .

In the given figure ABC is a right angled triangle with angleB=90^(@) . D is the mid -point of BC . Show that AC^(2) = AD^(2) +3CD^(2) .

In the given figure, triangle ABC is a right triangle with angleB=90^(@) and D is mid-point of side BC. Prove that : AC^(2)=AD^(2)+3CD^(2)

In a triangle ABC, B=90^@ and D is the mid-oint of BC then prove that AC^2=AD^2+3 CD^2

In Figure,ABC is a right triangle right angled at B and points DandE trisect BC. Prove that 8AE^(2)=3AC^(2)+5AD^(2)