lf bara = 3i - 5j and barb = 6i + 3j are...

lf `bara = 3i - 5j` and `barb = 6i + 3j` are two vectors, and `barc` is a vector such that `barc = bara xx barb` ,
then : `abs(bara) : abs(barb) : abs(barc) =`

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