A quantity of gas occupies an initial volume `V_(0)` at pressure `p_(0)` and temperature `T_(0)`. It expands to a volume V (a) constant temperature and (b) constant pressure. In which case does the gas do more work ?

n moles of a gas expands from volume V_(1) to V_(2) at constant temperature T. The work done by the gas is

One mole of an ideal gas at pressure P_(0) and temperature T_(0) is expanded isothermally to twice its volume and then compressed at constant pressure to (V_(0) // 2) and the gas is brought bac to original state by a process in which P alpha V (pressure is directly proportional to volume). The correct temperature of the process is

One mole of an ideal gas at pressure P_(0) and temperature T_(0) is expanded isothermally to twice ist volume and then compressed at constant pressure to (V_(0) // 2) and the gas is brought bac to original state by a process in which P alpha V (pressure is direclty proportional to volume). The correct temperature of the process is

A gas is found to obey the law P^(2)V = constant . The initial temperature and volume are T_(0) and V_(0) . If the gas expands to a volume 3 V_(0) , its final temperature becomes

A gas is found to obey the law P^(2)V = constant . The initial temperature and volume are T_(0) and V_(0) . If the gas expands to a volume 3 V_(0) , its final temperature becomes

A gas is found to obey the law p^(2) V = constant. The initial temperature and volume are T_(0) and V_(0) . If the gas expands to a volume 3V_(0) , its final temperature becomes