If `y=5(mm) sin pi t` is equation of oscillation of source `S_(1)` and `y_(2) = 5 (mm) sin pi//6)` be that of `S_(2)` and it takes `1 sec` and `^(1//_(2 sec)` for the transverse waves to reach point `A` from source `S_(1)` and `S_(2)` respectively then the resulting amplitude at point `A`, is
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Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

In the case of light waves from two coherent sources S_(1) and S_(2) , there will be constructive interference at an arbitrary point P, the path difference S_(1)P - S_(2)P is

In the case of light waves from two coherent sources S_(1) and S_(2) , there will be constructive interference at an arbitrary point P, the path difference S_(1)P - S_(2)P is

Ratio waves originating from sources S_(1) and S_(2) having zero phase difference and common wavelength lambda will show completely destructive interference at a point P is S_(1)P-S_(2)P is

S_1 and S_2 are two coherent sources of radiations separated by distance 100.25 lambda , where lambda is the wave length of radiation. S_1 leads S_2 in phase by pi//2 .A and B are two points on the line joining S_1 and S_2 as shown in figure.The ratio of amplitudes of component waves from source S_1 and S_2 at A and B are in ratio 1:2. The ratio of intensity at A to that of B (I_A/I_B) is

S_1 and S_2 are two coherent sources of radiations separated by distance 100.25 lambda , where lambda is the wave length of radiation. S_1 leads S_2 in phase by pi//2 .A and B are two points on the line joining S_1 and S_2 as shown in figure.The ratio of amplitudes of component waves from source S_1 and S_2 at A and B are in ratio 1:2. The ratio of intensity at A to that of B (I_A/I_B) is

S_1 and S_2 are two coherent sources of radiations separated by distance 100.25 lambda , where lambda is the wave length of radiation. S_1 leads S_2 in phase by pi//2 .A and B are two points on the line joining S_1 and S_2 as shown in figure.The ratio of amplitudes of component waves from source S_1 and S_2 at A and B are in ratio 1:2. The ratio of intensity at A to that of B (I_A/I_B) is

When two waves y _(1) =A sin (omega t + (pi)/(6)) and y _(2) = A cos (omega t) superpose, find amplitude of resultant wave.