The equation of a plane which is perpendicular to `(2hati-3hatj+hatk)` and at a distance of 5 units from the origin is

The equation of the plane with normal 2 hati + hatj -2 hat k and at distance 5 units from the origin is...........

The vector equation of a plane is vecr.(2hati+2hatj-hatk)=21 , find the length of the perpendicular from the origin to the plane.

Find the vector equation of a plane which is at a distance of 7 units from the origin and which is normal to the vector 3 hati + 5 hatj - 6 hatk . (ii) Find the vector equation of a plane , which is at a distance of 5 units from the origin and its normal vector is 2 hati - 3 hatj + 6 hatk .

Find the vector equation of a plane, which is at a distance of 5 units from the origin and its normal vector is 2hati-3hatj+6hatk .

Find the vector equation of a plane which is at a distance of 5 units from the origin and whose normal vector is 2 hati - hatj + 2 hatk .

The equation of the plane through the intersection of the planes vecr.(2hati+6hatj)+12=0 and vecr.(3hati-hatj+4hatk)=0 and at a unit distance from the origin, is

Find the vector equation of a plane which is at a distance of 4 units from the origin and which has (2hati-3hatj+6hatk) as the normal vector.

Find the vector equation of the plane which is at a distance of 5 units from the origin and which is normal to the vector 2hati + hatj + 2hatk .

Find the vector equation of a plane, which is at a distance of 7 units from the origin and which is normal to the vector 3hati+5hatj-6hatk .

The vector equation of the plane which is at a distance of 8 units from the origin which is normal to the vector 2hati+hatj+2hatk is