A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point O, and `PO=OQ`. The distance `PO`

A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The center of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The ling PQ cuts the surface at a point O, and PO=OQ . The distance PO is equal to

A spherical surface radius of curvatue R seprates air (refractive index 1.0) from glass 9refractive index 1.5).The centre of curvature is in the glass.A point object P is placed in air is found to have a real image Q in the glass.The line PQ cuts the surface at a point O and PO = OQ[Fig.2.47].Find the distance of object from the shperical surface. .

The refractive index of glass with respect to air is 1.6. The refractive index of air w.r.t. glass is