For a body to escape from earth, angle from horizontal at which it should be fired is

If the escape velocity of the body which is thrown from earth surface is V_e , then the escape velocity of the body if it is thrown at an angle theta from horizontal earth s surface is

The value of the escape velocity of a body thrown vertically upwards from the surface of the earth is v. if the body is thrown making an angle theta with the vertical, then the value of the escape velocity will be

The escape velocity of a body from the surface of the earth is V_(1) and from an altitude equal to twice the radius of the earth, is, V_(2) . Then

Does the escape speed of a body from the earth depend on the height of the location from where the body is launched?

A body is projected up from the surface of the earth with a velocity half the escape velocity at an angle of 30^(@) with the horizontal. Neglecting air resistance and earth’s otation, find (a) the maximum height above the earth’s surface to which the body will rise. (b) will the body move around the earth as a satellite?

Does the escape speed of a body from the Earth depend on , the height of the location from where the body is launched ? Explain your answer.

Does the escape speed of a body from the earth depend on:- the height of the location from where the body is launched?

An object is projected from the earth's surface with escape velocity at 30^(@) with horizontal. What is the angle made by the velocity with horizontal when the object reaches a height 2R from the earth's surface ? R is the radius of the earth. Horizontal can be considered as a line parallel to the tangent at the earth's surface just below the object .