The wave function for 2s orbital is given as:
`Psi = ((1)/(sqrt2)) ((1)/(alpha_(0)))^(3//2)(2- (r)/(alpha_(0))).e^(-r//2alpha_(0)`
Where `alpha_(0)`= First Bohr's radius in H-atom =0.529 "Å" Read the given statement and pick out the correct statement(s).

Given wave function represents which orbital of hydrogen Psi=1/4 1/(sqrt2pi)(1/(alpha_(0)))^(5//2) re^(-r//2alpha)cos 0 (where 0=angle from z-axis)

The schrodinger wave equation for hydrogen atom is Psi_2 = (1)/(4sqrt(2pi))((1)/(a_0))^(3//2) (2-(r)/(a_0))e^(-r//a_0) where a_0 is Bohr.s radius. If the radial node in 2s be at r_0 would be equal to

The Schrodinger wave equation for hydrogen atom is Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0)) , where a_(0) is Bohr's radius . If the radial node in 2s be at r_(0) , then r_(0) would be equal to :

The Schrodinger wave equation for hydrogen atom is Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0)) , where a_(0) is Bohr's radius . If the radial node in 2s be at r_(0) , then r_(0) would be equal to :

The Schrodinger wave equation for hydrogen atom is Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0)) , where a_(0) is Bohr's radius . If the radial node in 2s be at r_(0) , then r_(0) would be equal to :

The Wave function (Psi) of 2s is given by: Psi_(2s)=(1)/(2sqrt2pi)(1/a_(0))^(1//2){2-(r)/a^(0)}e^(-r//2a_(0)) At r =r_(0) , radial node is formed . Thus for 2s ,r_(0), in terms of a_(0) is-

a.The schrodinger wave equation for hydrogen atom is psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^((3)/(2)) (2 - (r_(0))/(a_(0)))e^((-(r )/(a)) When a_(0) is Bohr's radius Let the radial node in 2s be n at Then find r_(0) in terms of a_(0) b. A base ball having mass 100 g moves with velocity 100 m s^(-1) .Find the value of teh wavelength of teh base ball