Calculate the pressure exerted by `10^(23)` gas molecules each of mass `10^(-22) g` in a container of volume 1 litre the rms speed is `10^(5) cm s^(-1)`

The pressure exerted by 10^(23) gas molecules, each mass 10^(-22) g in a container of volume one litre, the RMS velocity of molecule is 10^(5) cm sec^(-1)

Calculate the pressure exerted by 10^(23) gas particles each of mass 10^(- 22) g in a container of volume 1 dm^(3) . The root mean square speed is 10^(5) cms^(- 1)

Calculate the pressure exerted by 10^(23) gas particles each of mass 10^(- 22) g in a container of volume 1 dm^(3) . The root mean square speed is 10^(5) cms^(- 1)

What is the pressure exerted by 10^(23) gas molecules, each molecule of mass 10^(-23) g, present in a container of volume one L and RMS speed of 1000 m s^(-1) ?

Calculate the rms speed of an ideal gas molecule of mass 2.99xx10^(-25) kg at 300k.

In a container of volume 1L, there are 10^(23) gas molecules, each of which has a mass of 10^(-22) g. at a certain temperature, if the rms velocity of these molecules is 10^(5)cm*s^(-1) , then what would be the pressure at the temperature inside the container?

Calculate the pressure exerted by 10 moles of neon gas in a 5 L container at 27^(@)C , using the ideal gas equation.