If the square of an odd natural number is divisible by 8, then the remainder will be 1        (b) 2      (c) 3     (d) 4

Prove that the square of an odd natural number when divided by 8 always gives the remainder 1.

When the square of any odd number, greater than 1, is divided by 8, it always leaves remainder is

When the square of any odd number, greater than 1, is divided by 8, it always leaves remainder

When the square of any odd number, greater than 1, is divided by 8, it always leaves remainder (a) 1 (b) 6 (c) 8 (d) Cannot be determined

When the square of any odd number, greater than 1, is divided by 8, it always leaves remainder (a)1 (b) 6 (c) 8 (d) Cannot be determined

When the square of any odd number, greater than 1, is divided by 8, it always leaves remainder 1 (b) 6 (c) 8 (d) Cannot be determined

The sum of first n odd natural numbers is 2n-1 (b) 2n+1 (c) n^2 (d) n^2-1

The sum of first n odd natural numbers is 2n-1 (b) 2n+1 (c) n^2 (d) n^2-1

A number divided by 68 given the quotient 260 and remainder zero. If the same number is divided by 65, the remainder is 0 (b) 1 (c) 2 (d) 3