If `tanalpha` is equal to the integral solution of the inequality `4x^2-16 x+15<0` and `cosbeta` is equal to the slope of the bisector of the first quadrant, then `sin(alpha+beta)sin(alpha-beta)` is equal to (a)`3/5` (b) `3/5` (c) `2/(sqrt(5))` (d) `4/5`

If tan alpha is equal to the integral solution of the inequality 4x^(2)-16x+15<0 and cos beta is equal to the slope of the bisector of the first quadrant,then sin(alpha+beta)sin(alpha-beta) is equal to (a)(3)/(5) (b) (3)/(5) (c) (2)/(sqrt(5)) (d) (4)/(5)

If tan alpha is equal to the integral solution of the inequality 4x^(2)-16x+15lt0 and cos beta is equal to the slope of the bisector of the coordinate axes in the first quadrant, then sin(alpha+beta)sin(alpha-beta) is equal to

If cot alpha equals the integral solution of inequality 4x ^(2)-16x+15 le 0 and sin beta equals to the slope of the bisector of the first quadrant, then sin (alpha+ beta) sin (alpha - beta) is equal to:

In the following incomplete sentences fill in the blanks such that the resulting sentences become true. If tan alpha is an integral solution of the inequation 4x^(2) -16x + 15 lt 0 and cos beta is the slope of the bisector of the angle in the first quadrant between the x and y axes then the value of sin(alpha +beta)* sin(alpha - beta) =__________.

4x^(2)+16x+15

The solution set of the inequality 4x+3<6x+7 is

Number of integral solutions of inequality |x+3|>|2x-1| is

The solution of the inequality log_(x)(4x^(2)-1)<2, is