A bar magnet of `5 cm` long having a pole strenght of `20 A.m`. Is deflected through `30^(@)` from the magnetic meridian. If `H=(320)/(4pi)A//m`, the deflecting couple is

A magnet 10 cm and having a pole strength of 8 units is deflected through 45^(@) from the magnetic meridian. If the earth's magnetic field is 0.32 oersted, value of the deflecting couple in dynes cm will be

A magnet 10 cm and having a pole strength of 8 units is deflected through 45^(@) from the magnetic meridian. If the earth's magnetic field is 0.32 oersted, value of the deflecting couple in dynes cm will be

A magnet of dipole moment 2Am^(2) is deflected through 30^(@) from magnetic meridian. The required deflecting torque is (B_(H)=0.4xx10^(-4)T)

A magnet of dipole moment 2Am^(2) is deflected through 30^(@) from magnetic meridian. The required deflecting torque is (B_(H)=0.4xx10^(-4)T)

The work done in rotating a magnet of pole strength 1 A-m and length 1 cm through an angle of 60^(@) from the magnetic meridian is (H=30A//m)

Magnetic field due to a bar magnet 2 cm long having a pole strength of 100 Am at a point 10 cm from each pole is

A dipole of magnetic moment (2.5 Am^2) is deflected through 30° from magnetic meridian. If the earth's horizontal field is (0.4x10^-4) I calculate the deflection moment.

A magnet of magnetic dipole moment 2Am2 is deflected through 30^@ from the direction of a magnetic field of induction 2frac(Wb)(m^2) . Find the magnitude of the torque.

A magnet of magnetic dipole moment 4 Am^(2) is deflected though 45^(@) from the direction of a magnetic field of induction 3sqrt(2)" Wb/m"^(2) . What is the magnitude of the torque on the magnet?