Lines `(x-1)/2 = (y-2)/3 = (z-3)/4` and `(x-2)/3 = (y-3)/4 = (z-4)/5` lie on the plane

The lines (x-1)/(a) = (y-2)/(3) = (z-3)/(4) , (x-2)/(3) = (y-3)/(4) = (z-4)/(5) are coplanar. Then a=

Show that the lines (x-1)/2=(y-2)/3=(z-3)/4 and (x-2)/3=(y-3)/4=(z-4)/5 are coplanar. Also find the equation of the plane containing the lines.

Prove that the stright line (x-1)/(2)=(y-2)/(3)=(z-3)/(4) and (x-2)/(3)=(y-3)/(4)=(z-4)/(5) are coplanar and find the equation of the plane in which they lie.

Lines whose equation are (x-3)/2=(y-2)/3=(z-1)/(lamda) and (x-2)/3=(y-3)/2=(z-2)/3 lie in same plane, then. Angle between the plane containing both lines and the plane 4x+y+2z=0 is

Lines whose equation are (x-3)/2=(y-2)/3=(z-1)/(lamda) and (x-2)/3=(y-3)/2=(z-2)/3 lie in same plane, then. Angle between the plane containing both lines and the plane 4x+y+2z=0 is

Two line whose are (x-3)/(2)=(y-2)/(3)=(z-1)/(lambda) and (x-2)/(3)=(y-3)/(2)=(z-2)/(3) lie in the same plane, then, Q. Angle between the plane containing both the lines and the plane 4x+y+2z=0 is equal to

Two line whose are (x-3)/(2)=(y-2)/(3)=(z-1)/(lambda) and (x-2)/(3)=(y-3)/(2)=(z-2)/(3) lie in the same plane, then, Q. Angle between the plane containing both the lines and the plane 4x+y+2z=0 is equal to

The point of intersection of lines (x-1)/(2)=(y-2)/(3)=(z-3)/(4) and (x-4)/(5)=(y-1)/(2)=(z)/(1) is

" The point of intersection of lines "(x-1)/(2)=(y-2)/(3)=(z-3)/(4)" and "(x-4)/(5)=(y-1)/(2)=(z)/(1)" is "