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xy = log (xy)...

xy = log (xy)

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If log (x+y) =log (xy ) +a, then (dy)/(dx) =

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1/(log_(xy)x + log_(xy)y = _______ ?

xy = log y + C : y' = (y^(2))/(1 - xy)(xy ne 1)

xy = log y + C : y' = (y^(2))/(1 - xy)(xy ne 1)

xy = log y + C : y' = (y^(2))/(1 - xy)(xy ne 1)