`int_(0)^(pi//2)(a sin x + b cos x)/(sin x + cos x) dx=`

int_(0)^(pi//2)(200 sin x + 100 cos x)/(sin x + cos x) dx =

int_(0)^(pi//2)(sin x - cos x)/(1-sin x cos x)dx=

int_(0)^(pi//2) ""(sin x - cos x)/( 1-sin x * cos x) dx is equal to

Prove that int_(0)^(a) f(x) dx = int_(0)^(a) f(a-x) dx . Hence, evaluate int_(0)^(pi//2) (sin x - cos x)/(1+ sin x cos x) dx.

Prove that int_(0)^(pi//2) (sin x -cos x)/(1+sin x cos x)dx = 0 .

int_(0)^(pi//2) x sin x cos x dx

int_(0)^(pi//2) x sin x cos x dx

int_(0)^((pi)/(2)) ( sin x - cos x )/( 1+ sin x cos x ) dx = ".............."