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((0. 6)^4-(0. 5)^4)/((0. 6)^2+(0. 5)^2) ...

`((0. 6)^4-(0. 5)^4)/((0. 6)^2+(0. 5)^2)` is equal to (a) 0.1 (b) 0.11 (c) 1.1 (d) 11

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Let A=[(1,0,0),(0,1,1),(0,-2,4)],I=[(1,0,0),(0,1,0),(0,0,1)] and A^-1=[1/6(A^2+cA+dI)] Then value of c and d are (a) (-6,-11) (b) (6,11) (c) (-6,11) (d) (6,-11)