Home
Class 11
CHEMISTRY
PCl5 in solid state exists as PCl4^+ and...

`PCl_5` in solid state exists as `PCl_4^+` and `PCl_6^-` Also in some solvents it undergoes dissoctation as `2PCl_5 hArr PCl_2^+ +PCl_6^-`.
The oxidation number of `P` in `PCl_5 .PCl_4^+ ` and `PCl_6^-` are respectively :

Promotional Banner

Similar Questions

Explore conceptually related problems

PCl_5 in solid state exists as PCl_4^+ and PCl_6^- Also in some solvents it undergoes dissoctation as 2PCl_5 hArr PCl_2^+ +PCl_6^- . Which statement is wrong ?

PCl_5 in solid state exists as PCl_4^+ and PCl_6^- Also in some solvents it undergoes dissoctation as 2PCl_5 hArr PCl_2^+ +PCl_6^- . The geometry and hybridisation of PCl_6^- is :

PCl_5 in solid state exists as PCl_4^+ and PCl_6^- Also in some solvents it undergoes dissoctation as 2PCl_5 hArr PCl_2^+ +PCl_6^- . The geometry and hybridisation of PCl_4^+ is :

PCl_5 in solid state exists as PCl_4^+ and PCl_6^- . Also in some solvents it undergoes dissoctation as 2PCl_5 hArr PCl_2^+ +PCl_6^- . The geometry and hybridisation of PCl_5 is :

PCl_(5) in solid state exists as PCl_(4)^(+) and PCl_(6)^(-) and also in some solvents it undergoes dissociation as 2PCl_(5) hArr PCl_(4)^(+) +PCl_(6)^(-) Which statement is wrong ?

PCl_(5) in solid state exists as PCl_(4)^(+) and PCl_(6)^(-) and also in some solvents it undergoes dissociation as 2PCl_(5) hArr PCl_(4)^(+) +PCl_(6)^(-) The geometry and hybridisation of PCl_(6)^(-) is

PCl_(5) in solid state exists as PCl_(4)^(+) and PCl_(6)^(-) and also in some solvents it undergoes dissociation as 2PCl_(5) hArr PCl_(4)^(+) +PCl_(6)^(-) The geometry and hydridisation of PCl_(4)^(+) is

PCl_5 in solid state exists as PCl_4^+ and PCl_6^- Also in some solvents it undergoes dissoctation as 2PCl_5 hArr PCl_2^+ +PCl_6^- . The van't Hoff factor for diassociation of PCl_5 is (if alpha is its degree of disssociation) :

Solid PCl_5 exists as