Find the modulus : `(2)/(1+cos theta+isin theta)`

If theta is real then the modulus of (1)/(1 + cos theta + isin theta) is

(1)/(cos theta-isin theta) Find modulus

If (2 sin theta )/(1+ cos theta + sin theta )=x, find the value of (1- cos theta + sin theta )/(1+ sin theta )

Simplify : ((1+ cos theta - isin theta)/(1+cos theta + i sin theta))^5

Evaluate the following determinants: (b) |(cos theta, -sin theta),(sin theta, cos theta)| = cos theta (cos theta) - sin theta(-sin theta) = cos^(2) theta + sin^(2) theta = 1

Find the value of sqrt((1+cos theta)/(1-cos theta))+sqrt((1-cos theta)/(1+cos theta))

The modulus of the complex number ((1-isqrt3)(cos theta+isin theta))/(2(1-i) (cos theta-i sin theta)) is

If (1 + cos theta + isin theta) (1 + cos 2 theta + isin 2theta) = x + iy then y =

If (1 + cos theta - isin theta) ( 1+ cos 2 theta + isin 2 theta) = x +iy then x^(2) + y^(2) =