An electron is revolving round a proton, producing a magnetic field of `16 weber//m^(2)` in a circular orbit of radius `1 Å. Its angular velocity will be

An electron is revolving around a proton in a circular orbit of diameter 1 A^(@) . If it produces a megnetic field of 14 wb//m^(2) at the proton, then its angular velocity will be about

An electron is revolving around a proton in a circular path of diameter 0.1 nm. It produces a magnetic field 14 Wb m^-2 at the proton. The angular speed of the electron is

An electron in a hydrogen atom is considered to be revolving around a proton with a velocity (e^2)/(n) in a circular orbit of radius (n^2)/(me^2) . If I is the equivalent current, express it in terms of m, e, n.

An electron moving with velocity 2.2 xx 10^(6) m/s, revolving in circular orbit of radius 0.53 Å. Calculate its angular velocity.

An electron is revolving in a hydrogen atom in a circular orbit of radius 4Å making 10^(15)rps . What is the magnetic moment associated with this electron?

An electron in the ground state of hydrogen atom is revolving in anti clockwise direction in circular orbit of radius · R'. The orbital magnetic dipole moment of the electron will be

An electron in the ground state of hydrogen atom is revolving in anticlockwise direction in circular orbit of radius R. The orbital magnetic dipole moment of the electron will be

An electron in the ground state of hydrogen atom is revolving in anticlockwise direction in circular orbit of radius R. The orbital magnetic dipole moment of the electron will be