निम्न समीकरणों को पूरा कीजिएः
`._(88)Ba^(226)to._(86)Rn^(222)+…………….`

The kinetic energy of alpha - particles emiited in the decay of ._(88)Ra^(226) into ._(86)Rn^(222) is measured to be 4.78 MeV . What is the total disintegration energy or the 'Q' -value of this process ?

The kinetic energy of alpha - particles emiited in the decay of ._(88)Ra^(226) into ._(86)Rn^(222) is measured to be 4.78 MeV . What is the total disintegration energy or the 'Q' -value of this process ?

Consider the following nuclear fission reaction ._(88)Ra^(226) to ._(86)Rn^(222)+._(2)He^(4)+Q In the fission reaction. Kinetic energy of alpha -particle is 4.44 MeV. Find the energy emitted as gamma -radiation in keV in this reaction. m(._(88)Ra^(226))=226.005 amu m(._(86)Rn^(222))=222.000 amu

Consider the following nuclear fission reaciton ._(88)Ra^(226) to ._(86)Rn^(222)+._(2)He^(4)+Q In the fission reaction. Kinetic energy of alpha -particle is 4.44 MeV. Find the energy emitted as gamma -radiation in keV in this reaction. m(._(88)Ra^(226))=226.005 amu m(._(86)Rn^(222))=222.000 amu

The kinetic energy of alpha - particles emitted in the decay of ""_(88)Ra^(226) into ""_(86)Rn^(222) is measured to be 4.78 MeV. What is the total disintegration energy or the 'Q - value of this process ?

Complete the reaction : ""_88Ra^(226) to ""_86Rn^(222) + ?

A nucleus of radium (._(88)Ra^(226)) decays to ._(86)Rn^(222) by emisson of alpha- particle (._(2)He^(4)) of energy 4.8MeV . If meass of ._(86)Rn^(222)=222.0 a.m.u mass of ._(2)He^(4) is 4.003 a.m.u. and mass of ._(88)Ra^(226) is 226.00826 a.m.u., then calculate the recoil energy of the daughter nucleus. Take 1 a.m.u. =931MeV

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