चतुर्भुज `ABCD` के विकर्ण `AC` और `BD` परस्पर चतुर्भुज के भीतर काटते है तो
`ar(ABCD)=ar(ABC)+ar(…….)`.

ABCD is a cyclic quadrilateral, Diagonal BD and AC intersect each other at E, If angle BEC =128^@ and angle ECD =25^@ then what is the measure of angle BAC ? ABCD एक चक्रीय चतुर्भुज है, विकर्ण BD और AC एक दूसरे को E पर काटती है, यदि angle BEC =128^@ और angle ECD =25^@ तो angle BAC का मान क्या होगा ?

IN the figure, P is a point in the interior of a parallelogram ABCD. Show that (i) ar(APB) + ar(PCD) = 1/2 ar (ABCD) (ii) ar (APD) + ar(PBC) = ar(APB) + ar (PCD)

ABCD is parallelogram and ABEF is a rectangle and DG is perpendicular on AB. Prove that (i) ar (ABCD) = ar(ABEF) (ii) ar (ABCD) = AB xx DG

ABCD is parallelogram and ABEF is a rectangle and DG is perpendicular on AB. Prove that (i) ar (ABCD) = ar(ABEF) (ii) ar (ABCD) = AB xx DG

ABCD is parallelogram and ABEF is a rectangle and DG is perpendicular on AB. Prove that (i) ar (ABCD) = ar(ABEF) (ii) ar (ABCD) = AB xx DG

ABCD is parallelogram and ABEF is a rectangle and DG is perpendicular on AB. Prove that (i) ar (ABCD) = ar(ABEF) (ii) ar (ABCD) = AB xx DG

In the given figure, diagonals AC and BD of quadrilateral ABCD interset at O such that OB = OD. If AB = CD, then show that : (i) ar (DOC) = ar (AOB) (ii) ar (DCB) = ar (ACB) (iii) DA || CB or ABCD is a parallelogram .

ABCD, DCFE and ABFE are parallelograms. Show that ar(ADE) = ar(BCF)

triangle ABC ~ triangle RQP and AB = 4 cm , BC = 6 cm and AC = 5 cm. If ar(triangle ABC) : ar (triangle PQR)=9:4 , then PQ is equals to : triangle ABC ~ triangle RQP है तथा AB = 4 सेमी, BC = 6 सेमी और AC = 5 सेमी है | यदि ar(triangle ABC) : ar (triangle PQR)=9:4 ,है, तो PQ किसके बराबर है ?

Diagonals AC and BD of square ABCD intersect each other at point P. Show that ar(/_APB)xx ar(/_CPD)=ar(/_APD)xx ar(/_BPC)