The rate constant for the first order decomposition of ethylene oxide into `CH_(4)` and CO,

may be describe by
`log k("in" s^(-1))=14.34-(1.25xx10^(4)K)/T`
The activation energy of the reaction is

Rate constant for the decomposition of ethylene oxide into CH_(4) and CO may be described be the equation. logk(s)^(-1)=14.34-(1.25xx10^(4))/(T) (a) What is the energy of activation of this reaction ? (b) What is the value of k at 670K ?

The rate constant for the first order decomposition of a certain reaction is described by the equation log k (s^(-1)) = 14.34 - (1.25 xx 10^(4)K)/(T) (a) What is the energy of activation for the reaction? (b) At what temperature will its half-life period be 256 min ?

The rate constant for the first order decompoistion of a certain reaction is described by the equation log k (s^(-1)) = 14.34 - (1.25 xx 10^(4)K)/(T) (a) What is the energy of activation for the reaction? (b) At what temperature will its half-life periof be 256 min ?

The rate constant for the decompoistion of a certain reaction is described by the equation: log k(s^(-1)) = 14 - (1.25 xx 10^(4) K)/(T) Energy of activation (in kcal ) is

The rate constant for the decompoistion of a certain reaction is described by the equation: log k(s^(-1)) = 14 - (1.25 xx 10^(4) K)/(T) Energy of activation (in kcal ) is

The rate constant for the decompoistion of a certain reaction is described by the equation: log k(s^(-1)) = 14 - (1.25 xx 10^(4) K)/(T) Pre-exponential factor for this reaction is