Find x `cos3x+sin(2x-(7pi)/6)=-2`

Find x cos3x+sin(2x-(7 pi)/(6))=-2

If cos3x+sin(2x-(7pi)/6)=-2 , then show that x is of the form π / 3(6m+1) .

If cos3x+sin(2x-(7pi)/6)=-2 , then show that x is of the form π / 3(6n+1) .

If cos 3x+sin (2x-(7pi)/6)=-2 , then x is equal to (k in Z)

If cos 3x+sin (2x-(7pi)/6)=-2 , then x is equal to (k in Z)

If cos3x+sin(2x-(7pi)/6)=-2 , then x is equal to (k in Z) pi/3(6k+1) (b) pi/3(6k-1) pi/3(2k+1) (d) none of these

If cos3x+sin(2x-(7 pi)/(6))=-2, then x is equal to (k in Z)(pi)/(3)(6k+1)( b) (pi)/(3)(6k-1)(pi)/(3)(2k+1)( d ) none of these

If "cos 3x + "sin" (2x - (7pi)/(6)) =-2 , then x =

If "cos 3x + "sin" (2x - (7pi)/(6)) =-2 , then x =