A planet has twice the radius but the mean density is `1/4` th as compared to earth. What is the ratio of escape velocity from earth to that from the planet

The mass of a planet is six times that of the earth. The radius of the planet is twice that of the earth. It's the escape velocity from the earth is v , then the escape velocity from the planet is:

The mass of a planet is six times that of the earth. The radius of the planet is twice that of the earth. If the escape velocity from the earth is v , then the escape velocity from the planet is:

Mass and radius of a planet are two times the value of earth. What is the value of escape velocity from the surface of this planet?

Mass and radius of a planet are two times the value of earth. What is the value of escape velocity from the surface of this planet?

Solve the following examples/numerical problems : If the mass of a planet is eight times the mass of the earth and its radius is twice the radius of the earth, what will be the ratio of the escape velocity on the earth to the escape velocity on the planet?

The escape speed from earth's surface is 11kms^(-1) . A certain planet has a radius twice that of earth but its mean density is the same as that of the earth. Find the value of the escape speed from the planet.

The escape speed from earth's surface is 11kms^(-1) . A certain planet has a radius twice that of earth but its mean density is the same as that of the earth. Find the value of the escape speed from the planet.

The value of the escape velocity from the earth is v_e . If the radius of a planet is 4 times that of the earth and its density is 9 times the density of the earth, then the value of the escape velocity from that planet will be

If the mass of a Planet is eight times the mass of the earth and its radius is twice the radius of the earth, what will be the escape velocity for that planet ?