`y^(2)=-8x`

If y=2 x+k is a tangent to y^(2)=8 x, then k=

The circle x ^(2) +y^(2) -8 x+4=0 touches -

The number of common tangents to x^(2)+y^(2)=8, x^(2)+y^(2)=2 is

The number of common tangents to x^(2)+y^(2)=8, x^(2)+y^(2)=2 is

Length of the latus rectum of the ellipse 2 x^(2)+y^(2)-8 x+2 y+7=0 is

A parabola has its vertex and focus in the first quadrant and axis along the line y=x . If the distances of the vertex and focus from the origin are respectively sqrt(2)&2sqrt(2) , then equation of the parabola is x^2+y^2-8x+8y+2x y=16 x^2+y^2-8x-8y+16=2x y (x-y)^2=8(x+y-2) (x+y)^2=(x-y+2)

Solve the following systems of inequation graphically: 2x+y>=8,x+2y>=8,x+y<=6