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In the given figure, the blocks of mass ...

In the given figure, the blocks of mass 2kg and 3kg are placed one over the other as shown. The surface are rough with coefficient of friction `mu_(1)=0.2, mu_(2)=0.06`. A force `F=0.5t` (where 't' in sec) is applied on upper block in the direction shown. Based on above data answers the following questions. `(g = 10 m//sec^(2))`

The frictional force acting between 3 kg block and ground w.r.t. time will vary as :

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