A capacitor is formed by two square metal plate of edge a,separated by a distance d.Dielectric constants`K_1 and K_2`are filled in the gap as shown in figure(31-E25).Find the capacitance.

A capacitor is formed by two square metal-plates of edge a, separated by a distance d. Dielectrics of dielectric constants K_(1) and K_(2) are filled in the gap as shown in fig. Find the capacitance.

Two dielectric slabs of dielectric constants K_1 and K_2 are filled in between two plates each of area A, of a parallel plate capacitor. Find net capacitance.

A parallel plate capacitor consists of two identical metal plates. Two dielectric slabs having dielectric donstants k_1 and k_2 are introduced in the space between two plates as shown below. Show that capacity of capacitor in arrangement (a) is given by , C = (epsilon_0 (k_1+k_2)A)/(2d)

A paralled plate capacitor is made of two square plates of side 'a' , separated by a distance d (dltlta). The lower triangular portion is filled with a dielecttic of dielectric constant K, as shown in the figure. Capacitance of this Capacitor is :

An air capacitor of capacitance C plate area A and plate separation d has been filled with three dielectrics of constant k_(1)=3 , k_(2)=6 and k_(3)=4 as shown in figure . What is the new capacitance ?

An air capacitor of capacitance C plate area A and plate separation d has been filled with three dielectrics of constant k_(1)=3 , k_(2)=6 and k_(3)=4 as shown in figure . What is the new capacitance ?

A parallel plate capacitor has the space between its plates filled by two slabs of thickness (d)/(2) each and dielectric constant K_(1) and K_2 . d is the plate separation of the capacitor. The capacitance of the capacitor is